Question:

Find the value of the integral: \[ \int_0^e \log_e x \, dx \]

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For integrals involving logarithms, use integration by parts to simplify the expression.
Updated On: Apr 2, 2025
  • \( 1 \)
  • \( e - 1 \)
  • \( \frac{e}{2} - 1 \)
  • \( 0 \)
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The Correct Option is C

Solution and Explanation

We are tasked with evaluating the integral: \[ I = \int_0^e \log_e x \, dx \] To solve this, we can use integration by parts. The formula for integration by parts is: \[ \int u \, dv = uv - \int v \, du \] Let: \[ u = \log_e x, \quad dv = dx \] Then: \[ du = \frac{1}{x} dx, \quad v = x \] Now, applying the integration by parts formula: \[ I = x \log_e x \bigg|_0^e - \int_0^e x \cdot \frac{1}{x} dx \] \[ I = e \log_e e - 0 \cdot \log_e 0 - \int_0^e 1 \, dx \] \[ I = e \cdot 1 - 0 - \left[ x \right]_0^e \] \[ I = e - (e - 0) = e - e = 0 \] Therefore, the correct answer is \( 0 \).
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