Question:

A region in the form of an equilateral triangle (in x-y plane) of height L has a uniform magnetic field 𝐡⃗ pointing in the +z-direction. A conducting loop PQR, in the form of an equilateral triangle of the same height 𝐿, is placed in the x-y plane with its vertex P at x = 0 in the orientation shown in the figure. At 𝑑 = 0, the loop starts entering the region of the magnetic field with a uniform velocity 𝑣 along the +x-direction. The plane of the loop and its orientation remain unchanged throughout its motion.
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Which of the following graph best depicts the variation of the induced emf (E) in the loop as a function of the distance (π‘₯) starting from π‘₯ = 0?

Updated On: June 02, 2025
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The Correct Option is A

Approach Solution - 1

To solve the problem, we need to analyze the variation of the induced emf in a conducting triangular loop moving through a region of uniform magnetic field.

1. Understanding the Setup:
- The loop PQR is an equilateral triangle of height \( L \) moving along the \( +x \)-direction.
- The magnetic field \( \vec{B} \) is uniform and points in the \( +z \)-direction.
- At \( x=0 \), vertex P enters the magnetic field region.
- The induced emf \( E \) is related to the rate of change of magnetic flux through the loop.

2. Variation of Flux and emf:
- Initially, no part of the loop is inside the magnetic field, so \( E = 0 \).
- As the loop enters the field (from \( x=0 \) to \( x=L \)), the area inside the field increases linearly, so flux increases linearly.
- The emf \( E = -d\Phi/dt \) is proportional to the rate of change of flux.
- When half the loop enters (\( x=L/2 \)), the rate of change of area changes slope.
- Between \( x=L \) and \( x=2L \), the loop is leaving the field and the flux decreases.
- Beyond \( x=2L \), the loop is completely outside, so \( E = 0 \).

3. Shape of emf vs. distance graph:
- The emf starts at zero at \( x=0 \), decreases (negative slope) until \( x=L/2 \), then increases until \( x=L \).
- After \( x=L \), emf is zero until \( x=3L/2 \), then increases positively until \( x=2L \), and finally returns to zero.
- This corresponds to graph (A) with negative and positive triangular peaks.

Final Answer:
Option (A)

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Approach Solution -2

To solve the problem, analyze how the induced emf in the loop changes as the loop moves through the magnetic field region.

1. Setup:
- The loop PQR is an equilateral triangle of height \(L\), moving along the +x direction.
- Magnetic field \(\vec{B}\) is uniform and directed along +z.
- Induced emf \(E\) is related to the rate of change of magnetic flux through the loop.
- At \(x=0\), vertex P enters the magnetic field region.

2. Flux and emf behavior:
- For \(0 \leq x < L\): increasing part of the loop enters the field.
- The flux increases non-linearly, first faster then slower due to triangular shape.
- This results in a changing induced emf with negative and positive slopes at different points.
- For \(L \leq x \leq 2L\): the loop leaves the magnetic field region.
- The flux decreases similarly, giving a characteristic emf pattern.

3. Graph Interpretation:
- The induced emf first decreases (negative peak) as the loop enters.
- Then it increases to zero at \(x=L\).
- After that, it stays zero for some region.
- Finally, it increases positively as the loop leaves the field and goes back to zero at \(x=2L\).
- This matches graph (A).

Final Answer:
Option (A)

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