To solve the problem, we need to analyze the variation of the induced emf in a conducting triangular loop moving through a region of uniform magnetic field.
1. Understanding the Setup:
- The loop PQR is an equilateral triangle of height \( L \) moving along the \( +x \)-direction.
- The magnetic field \( \vec{B} \) is uniform and points in the \( +z \)-direction.
- At \( x=0 \), vertex P enters the magnetic field region.
- The induced emf \( E \) is related to the rate of change of magnetic flux through the loop.
2. Variation of Flux and emf:
- Initially, no part of the loop is inside the magnetic field, so \( E = 0 \).
- As the loop enters the field (from \( x=0 \) to \( x=L \)), the area inside the field increases linearly, so flux increases linearly.
- The emf \( E = -d\Phi/dt \) is proportional to the rate of change of flux.
- When half the loop enters (\( x=L/2 \)), the rate of change of area changes slope.
- Between \( x=L \) and \( x=2L \), the loop is leaving the field and the flux decreases.
- Beyond \( x=2L \), the loop is completely outside, so \( E = 0 \).
3. Shape of emf vs. distance graph:
- The emf starts at zero at \( x=0 \), decreases (negative slope) until \( x=L/2 \), then increases until \( x=L \).
- After \( x=L \), emf is zero until \( x=3L/2 \), then increases positively until \( x=2L \), and finally returns to zero.
- This corresponds to graph (A) with negative and positive triangular peaks.
Final Answer:
Option (A)
To solve the problem, analyze how the induced emf in the loop changes as the loop moves through the magnetic field region.
1. Setup:
- The loop PQR is an equilateral triangle of height \(L\), moving along the +x direction.
- Magnetic field \(\vec{B}\) is uniform and directed along +z.
- Induced emf \(E\) is related to the rate of change of magnetic flux through the loop.
- At \(x=0\), vertex P enters the magnetic field region.
2. Flux and emf behavior:
- For \(0 \leq x < L\): increasing part of the loop enters the field.
- The flux increases non-linearly, first faster then slower due to triangular shape.
- This results in a changing induced emf with negative and positive slopes at different points.
- For \(L \leq x \leq 2L\): the loop leaves the magnetic field region.
- The flux decreases similarly, giving a characteristic emf pattern.
3. Graph Interpretation:
- The induced emf first decreases (negative peak) as the loop enters.
- Then it increases to zero at \(x=L\).
- After that, it stays zero for some region.
- Finally, it increases positively as the loop leaves the field and goes back to zero at \(x=2L\).
- This matches graph (A).
Final Answer:
Option (A)
A square Lamina OABC of length 10 cm is pivoted at \( O \). Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of \( F \) is:
The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____
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Then the value of $ pq $ is