When dealing with direction cosines, remember that the sum of the squares of the direction cosines is always equal to 1. This property can help you solve for unknown angles when given the other angles.
The correct answer is: (C): \(\frac{\pi}{4}\)
We are given that the line makes an angle of \( \frac{\pi}{3} \) with both the X-axis and the Y-axis, and we are asked to find the acute angle it makes with the Z-axis.
Step 1: Understand the direction cosines
The direction cosines of a line are the cosines of the angles the line makes with the coordinate axes. If the line makes angles \( \alpha \), \( \beta \), and \( \gamma \) with the X, Y, and Z axes respectively, then the direction cosines are given by:
\( \cos \alpha, \cos \beta, \cos \gamma \)
Step 2: Use the known angles
We are told that the line makes an angle of \( \frac{\pi}{3} \) with both the X-axis and the Y-axis. Therefore, the direction cosines for the X and Y axes are:
\( \cos \alpha = \cos \beta = \cos \frac{\pi}{3} = \frac{1}{2} \)
Step 3: Use the property of direction cosines
The sum of the squares of the direction cosines of a line is always equal to 1. Therefore, we have:
\( \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 1 \)
Substitute \( \cos \alpha = \cos \beta = \frac{1}{2} \) into the equation:
\( \left( \frac{1}{2} \right)^2 + \left( \frac{1}{2} \right)^2 + \cos^2 \gamma = 1 \)
Simplifying:
\( \frac{1}{4} + \frac{1}{4} + \cos^2 \gamma = 1 \)
\( \frac{2}{4} + \cos^2 \gamma = 1 \)
\( \cos^2 \gamma = \frac{2}{4} = \frac{1}{2} \)
Step 4: Solve for \( \gamma \)
Now, take the square root of both sides:
\( \cos \gamma = \frac{1}{\sqrt{2}} \)
Therefore, the acute angle \( \gamma \) is:
\( \gamma = \frac{\pi}{4} \)
Conclusion:
The acute angle made by the Z-axis is \( \frac{\pi}{4} \), so the correct answer is (C): \(\frac{\pi}{4}\).
Show that the following lines intersect. Also, find their point of intersection:
Line 1: \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} \]
Line 2: \[ \frac{x - 4}{5} = \frac{y - 1}{2} = z \]
The vector equations of two lines are given as:
Line 1: \[ \vec{r}_1 = \hat{i} + 2\hat{j} - 4\hat{k} + \lambda(4\hat{i} + 6\hat{j} + 12\hat{k}) \]
Line 2: \[ \vec{r}_2 = 3\hat{i} + 3\hat{j} - 5\hat{k} + \mu(6\hat{i} + 9\hat{j} + 18\hat{k}) \]
Determine whether the lines are parallel, intersecting, skew, or coincident. If they are not coincident, find the shortest distance between them.
Determine the vector equation of the line that passes through the point \( (1, 2, -3) \) and is perpendicular to both of the following lines:
\[ \frac{x - 8}{3} = \frac{y + 16}{7} = \frac{z - 10}{-16} \quad \text{and} \quad \frac{x - 15}{3} = \frac{y - 29}{-8} = \frac{z - 5}{-5} \]
You are given a dipole of charge \( +q \) and \( -q \) separated by a distance \( 2l \). A sphere 'A' of radius \( R \) passes through the centre of the dipole as shown below and another sphere 'B' of radius \( 2R \) passes through the charge \( +q \). Then the electric flux through the sphere A is