For an adiabatic process, the heat exchanged \( Q = 0 \), hence, the change in internal energy is equal to the work done on or by the system:
\[
Q = \Delta U + W = 0 \implies \Delta U = - W
\]
For an adiabatic process, the work done \( W \) is proportional to the change in temperature. Also, we know that:
\[
W = -n C_V \Delta T \quad \text{or} \quad |W| = n C_V \Delta T \propto T_2 - T_1
\]
Thus, both (B) and (E) are correct, making option (3) the correct answer.