The internal energy of air in $ 4 \, \text{m} \times 4 \, \text{m} \times 3 \, \text{m} $ sized room at 1 atmospheric pressure will be $ __ \times 10^6 \, \text{J} $.
(Consider air as a diatomic molecule)
Show Hint
For a diatomic molecule, the internal energy is calculated using the formula \( U = \frac{5}{2} P V \), where \( P \) is pressure and \( V \) is volume.
To find the internal energy of gas in the room.
\[
U = n C_v T = \frac{5}{2} R T
\]
\[
= \frac{5}{2} \times P V = \frac{5}{2} \times 10^5 \times 48 = 12 \times 10^6 \, \text{J}
\]