Question

Hell-Volhard Zelinsky reaction is used for the formation of

• A. Alcohols
• B. Aldehydes
• C. Ketones
• D. $\alpha$-halocarboxylic acids

Hint:

The Hell-Volhard Zelinsky reaction selectively halogenates the $\alpha$-position of carboxylic acids, leading to the formation of $\alpha$-halocarboxylic acids.

Answer 1

The Correct Option is D

The Hell-Volhard Zelinsky reaction is a halogenation reaction that involves the halogenation of the $\alpha$-position of carboxylic acids. This reaction produces $\alpha$-halocarboxylic acids.
Step 1: Reaction Overview.
In the Hell-Volhard Zelinsky reaction, bromine (or chlorine) is used to selectively halogenate the $\alpha$-position of a carboxylic acid. This reaction requires the presence of a catalyst like phosphorus tribromide (PBr\(_3\)).
Step 2: Evaluate the options.
- Option 1: Alcohols: This is not correct, as the Hell-Volhard Zelinsky reaction does not produce alcohols.
- Option 2: Aldehydes: This reaction does not result in aldehydes.
- Option 3: Ketones: Ketones are not the product of this reaction either.
- Option 4: $\alpha$-halocarboxylic acids: This is the correct answer. The Hell-Volhard Zelinsky reaction specifically produces $\alpha$-halocarboxylic acids.
Step 3: Conclusion.
The Hell-Volhard Zelinsky reaction is used to form $\alpha$-halocarboxylic acids.
Final Answer: \[ \boxed{\text{The correct answer is $\alpha$-halocarboxylic acids.}} \]