Question:
Given below are two statements:
Statement (I) : The NH2 group in Aniline is ortho and para directing and a powerful activating group.
Statement (II) : Aniline does not undergo Friedel- Craft’s reaction (alkylation and acylation). In the light of the above statements
Choose the most appropriate answer from the options given below :
Given below are two statements:
Statement (I) : The NH2 group in Aniline is ortho and para directing and a powerful activating group.
Statement (II) : Aniline does not undergo Friedel- Craft’s reaction (alkylation and acylation). In the light of the above statements
Choose the most appropriate answer from the options given below :
Statement (I) : The NH2 group in Aniline is ortho and para directing and a powerful activating group.
Statement (II) : Aniline does not undergo Friedel- Craft’s reaction (alkylation and acylation). In the light of the above statements
Choose the most appropriate answer from the options given below :
Updated On: Mar 21, 2025
- Both Statement I and Statement II are correct
- Both Statement I and Statement II are incorrect
- Statement I is incorrect but Statement II is correct
- Statement I is correct but Statement II is incorrect
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The Correct Option is A
Solution and Explanation
The NH2 group in aniline is a strong electron-donating group, making it ortho and para directing in electrophilic aromatic substitution. Aniline does not undergo Friedel-Crafts reactions due to the formation of a complex with AlCl3, deactivating the benzene ring.
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