Conc. HNO\(_3\)
When phenol reacts with concentrated nitric acid (HNO₃), it undergoes nitration primarily at the ortho and para positions relative to the hydroxyl group (-OH). The electron-donating effect of the hydroxyl group activates the aromatic ring for electrophilic substitution, making the ring more reactive towards nitration.
The nitration of phenol with concentrated nitric acid produces **2,4,6-Trinitrophenol (picric acid)**, which is a highly reactive compound. The reaction can be represented as: \[ \text{C}_6\text{H}_5\text{OH} + 3\text{HNO}_3 \rightarrow \text{C}_6\text{H}_2(\text{NO}_2)_3\text{OH} + 3\text{H}_2\text{O} \]
The hydroxyl group on phenol is an electron-donating group that activates the benzene ring, making it more susceptible to electrophilic attack. During nitration, the nitronium ion (\( \text{NO}_2^+ \)) attacks the ortho and para positions of the phenol ring, resulting in the formation of **2,4,6-Trinitrophenol**, also known as **picric acid**.
The nitration of phenol with nitric acid results in the formation of **2,4,6-Trinitrophenol (picric acid)**, which is a highly reactive compound due to the electron-donating effect of the hydroxyl group. The major product is formed at the ortho and para positions relative to the hydroxyl group.
Designate whether each of the following compounds is aromatic or not aromatic.
Find the IUPAC name of the compound.
The compound with molecular formula C\(_6\)H\(_6\), which gives only one monobromo derivative and takes up four moles of hydrogen per mole for complete hydrogenation has ___ \(\pi\) electrons.
Two batteries of emf's \(3V \& 6V\) and internal resistances 0.2 Ω \(\&\) 0.4 Ω are connected in parallel. This combination is connected to a 4 Ω resistor. Find:
(i) the equivalent emf of the combination
(ii) the equivalent internal resistance of the combination
(iii) the current drawn from the combination