(i) The first ionization enthalpy order for the given elements is correctly stated as \( \text{Na} < \text{Li} < \text{Cl} < \text{F} \). This is supported by the ionization energies (in kJ/mol):
\[\text{Na} \, (496) < \text{Li} \, (520) < \text{Cl} \, (1256) < \text{F} \, (1681)\]
(ii)The order of negative electron gain enthalpy for these elements is also correctly stated as \( \text{Na} < \text{Li} < \text{F} < \text{Cl} \).
The values (in kJ/mol) are:
\[\Delta_{\text{eg}}H : \text{Na} \, (-53), \, \text{Li} \, (-60), \, \text{F} \, (-328), \, \text{Cl} \, (-349)\]
Thus, both statements are true.

For \( \alpha, \beta, \gamma \in \mathbb{R} \), if \[ \lim_{x \to 0} \frac{x^2 \sin(\alpha x) + (\gamma - 1)e^{x^2}}{\sin(2x - \beta x)} = 3, \] then \( \beta + \gamma - \alpha \) is equal to:

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by:
If \( S \) and \( S' \) are the foci of the ellipse \[ \frac{x^2}{18} + \frac{y^2}{9} = 1 \] and \( P \) is a point on the ellipse, then \[ \min (SP \cdot S'P) + \max (SP \cdot S'P) \] is equal to: