The correct order of first ionization enthalpies among the given elements can be deduced based on periodic trends. In general, ionization enthalpy increases across a period from left to right due to increasing nuclear charge and decreases down a group due to an increase in atomic size. Additionally, elements with stable electronic configurations, such as half-filled or fully-filled orbitals, tend to have higher ionization enthalpies.
The general trend for ionization enthalpy in the periodic table is:
\( \text{Li} < \text{B} < \text{Be} < \text{C} < \text{O} < \text{N} < \text{F} < \text{Ne} \)
Among the given elements:
\( \text{E (B)} < \text{C (Be)} < \text{A (O)} < \text{B (N)} < \text{D (F)} \)
Hence, the correct order of first ionization enthalpy values is:
\( \text{E (B)} < \text{C (Be)} < \text{A (O)} < \text{B (N)} < \text{D (F)} \)
Match List I with List II.
In which of the following reactions of H$_2$O$_2$ acts as an oxidizing agent (either in acidic, alkaline, or neutral medium)?
% Given Reactions
(i) \( 2Fe^{2+} + H_2O_2 \rightarrow \)
(ii) \( 2MnO_4^- + 6H^+ + 5H_2O_2 \rightarrow \)
(iii) \( I_2 + H_2O_2 + 2OH^- \rightarrow \)
(iv) \( Mn^{2+} + H_2O_2 \rightarrow \)