Question

Match List I with List II. 
 

• A. A-II, B-I, C-IV, D-III
• B. A-II, B-IV, C-I, D-III
• C. A-II, B-III, C-I, D-IV
• D. A-I, B-II, C-IV, D-III

Hint:

Oxidation state calculations require balancing ligand charges with the overall charge of the complex. Carbonyl ligands are neutral and do not contribute to charge.

Answer 1

The Correct Option is A

Solution: To solve the matching problem, we will analyze the information given in List I and List II and assign the correct pairings based on our understanding of Chemistry.

List I	List II
A. Alkali Metals	II. Highly reactive metals not found free in nature
B. Noble Gases	I. Chemically inert and odorless
C. Transition Metals	IV. Have high melting points and densities
D. Halogens	III. Very reactive non-metals

Based on this analysis, the correct match from the options is:

A-II, B-I, C-IV, D-III

Answer 2

Oxidation Number Calculation Ni(CO)$_4$: Carbonyl (CO) is a neutral ligand. Since Ni has no charge, oxidation state is 0. 
[Fe(H$_2$O)$_5$NO]$^{2+$}: NO ligand contributes +1 oxidation state. Fe must be +1 to balance the charge. 
[Co(CO)$_5$]$^{2-$}: Since CO is neutral, oxidation state of Co is -2. 
[Cr$_2$(CO)$_{10}$]$^{2-$}: CO is neutral, so the total oxidation state of both Cr atoms is -2. Each Cr has -1 oxidation state. 
Final Answer: A-II, B-I, C-IV, D-III