Given below are two statements:
Statement-I: Figure shows the variation of stopping potential with frequency (v) for the two photosensitive materials M1 and M2. The slope gives value of \(\frac{h}{e}\) , where h is Planck's constant, e is the charge of electron.
Statement-II: M2 will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency. In the light of the above statements
Choose the most appropriate answer from the options given below.
Statement-I: Figure shows the variation of stopping potential with frequency (v) for the two photosensitive materials M1 and M2. The slope gives value of \(\frac{h}{e}\) , where h is Planck's constant, e is the charge of electron.
Statement-II: M2 will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency. In the light of the above statements
Choose the most appropriate answer from the options given below.
- Statement-I is correct and Statement-II is incorrect.
- Statement-I is incorrect but Statement-II is correct.
- Both Statement-I and Statement-II are incorrect.
- Both Statement-I and Statement-II are correct.
The Correct Option is A
Solution and Explanation
The stopping potential (\(V_0\)) is related to frequency (\(\nu\)) by the equation:
\[ eV_0 = h\nu - \phi \implies V_0 = \frac{h}{e}\nu - \frac{\phi}{e} \]
The slope of the graph gives \(\frac{h}{e}\), confirming Statement-I. However, \(M_2\) has a higher work function, meaning that for the same incident frequency, the kinetic energy of emitted photoelectrons will be lower. Therefore, Statement-II is incorrect.
Top Questions on Photoelectric Effect
- What is the ratio of de Broglie wavelength of the particles if their kinetic energy are 0.002 eV and 2 eV respectively?
- KEAM - 2025
- Physics
- Photoelectric Effect
- What is the ratio of de Broglie wavelength of the particles if their kinetic energy are 0.002 eV and 2 eV respectively?
- KEAM - 2025
- Physics
- Photoelectric Effect
- \( 10^{20} \) photons of wavelength 660 nm are emitted per second from a lamp. The wattage of the lamp is: \[ \text{(Planck's constant} \, h = 6.6 \times 10^{-34} \, \text{Js}) \]
- WBJEE - 2025
- Physics
- Photoelectric Effect
- A photo-emissive substance is illuminated with a radiation of wavelength $ \lambda_i $ so that it releases electrons with de-Broglie wavelength $ \lambda_e $. The longest wavelength of radiation that can emit photoelectron is $ \lambda_0 $. Expression for de-Broglie wavelength is given by : (m : mass of the electron, h : Planck's constant and c : speed of light)
- JEE Main - 2025
- Physics
- Photoelectric Effect
- What is the ratio of gyration of ring and disc?
- KEAM - 2025
- Physics
- Photoelectric Effect
Questions Asked in JEE Main exam
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
- JEE Main - 2025
- Matrix Algebra
The number of 6-letter words, with or without meaning, that can be formed using the letters of the word MATHS such that any letter that appears in the word must appear at least twice, is $ 4 \_\_\_\_\_$.
- JEE Main - 2025
- permutations and combinations
Let \( f : (0, \infty) \to \mathbb{R} \) be a twice differentiable function. If for some \( a \neq 0 \), } \[ \int_0^a f(x) \, dx = f(a), \quad f(1) = 1, \quad f(16) = \frac{1}{8}, \quad \text{then } 16 - f^{-1}\left( \frac{1}{16} \right) \text{ is equal to:}\]
- JEE Main - 2025
- integral
- Let \( S = \{ x : \cos^{-1} x = \pi + \sin^{-1} x + \sin^{-1} (2x + 1) \ \). Then \[ \sum_{x \in S} (2x - 1)^2 \text{ is equal to:} \]
- JEE Main - 2025
- Trigonometry
Let $L_1: \frac{x-1}{1} = \frac{y-2}{-1} = \frac{z-1}{2}$ and $L_2: \frac{x+1}{-1} = \frac{y-2}{2} = \frac{z}{1}$ be two lines. Let $L_3$ be a line passing through the point $(\alpha, \beta, \gamma)$ and be perpendicular to both $L_1$ and $L_2$. If $L_3$ intersects $L_1$, then $\left| 5\alpha - 11\beta - 8\gamma \right|$ equals:
- JEE Main - 2025
- Vectors