Question:

Given below are two statements:
Statement (I): A \(\pi\) bonding MO has lower electron density above and below the inter-nuclear axis.
Statement (II): The \(\pi^*\) antibonding MO has a node between the nuclei.
In the light of the above statements, choose the most appropriate answer from the options given below:

Updated On: Nov 27, 2024
  • Both Statement I and Statement II are false
  • Both Statement I and Statement II are true
  • Statement I is false but Statement II is true
  • Statement I is true but Statement II is false
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The Correct Option is C

Solution and Explanation

Statement (I) Analysis:
A $\pi$ bonding molecular orbital (MO) is formed by the sideways overlap of $p$-orbitals.
This type of bonding MO has higher electron density above and below the internuclear axis, leading to a bonding interaction between atoms.
Therefore, Statement (I) is false.
Statement (II) Analysis:
The $\pi^*$ antibonding molecular orbital is formed when $p$-orbitals combine in such a way that destructive interference occurs between the wave functions of the atomic orbitals.
This creates a node (a region of zero electron density) between the nuclei.
Therefore, Statement (II) is true.

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