Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The density of the copper ($^{64}Cu$) nucleus is greater than that of the carbon ($^{12}C$) nucleus.
Reason (R): The nucleus of mass number A has a radius proportional to $A^{1/3}$.
In the light of the above statements, choose the most appropriate answer from the options given below:
Step 1: Understanding Assertion (A)
- The assertion states that the density of the copper nucleus is greater than that of the carbon nucleus. However, this is incorrect. The density of atomic nuclei is approximately constant across different elements, regardless of the specific element. This is due to the fact that nuclear density depends mainly on the nuclear force and not on the element. Hence, assertion (A) is not correct.
Step 2: Understanding Reason (R)
- The radius of a nucleus is proportional to \(A^{1/3}\), where \(A\) is the mass number (total number of nucleons). This is a well-established empirical relation known as the "nuclear radius formula." This relation holds for all nuclei, including those of copper and carbon.
Therefore, reason (R) is correct.
Step 3: Connecting Assertion and Reason
- Although reason (R) is correct, it does not explain assertion (A) because the density of a nucleus does not depend on \(A^{1/3}\) in the way the assertion implies. The radius \(A^{1/3}\) only affects the volume, not the density in the way described in assertion (A).
Therefore, reason (R) is correct, but it is not the explanation for assertion (A).
Match the LIST-I with LIST-II
LIST-I (Type of decay in Radioactivity) | LIST-II (Reason for stability) | ||
---|---|---|---|
A. | Alpha decay | III. | Nucleus is mostly heavier than Pb (Z=82) |
B. | Beta negative decay | IV. | Nucleus has too many neutrons relative to the number of protons |
C. | Gamma decay | I. | Nucleus has excess energy in an excited state |
D. | Positron Emission | II. | Nucleus has too many protons relative to the number of neutrons |
Choose the correct answer from the options given below:
Match the LIST-I with LIST-II
\[ \begin{array}{|l|l|} \hline \text{LIST-I} & \text{LIST-II} \\ \hline A. \ ^{236}_{92} U \rightarrow ^{94}_{38} Sr + ^{140}_{54} Xe + 2n & \text{I. Chemical Reaction} \\ \hline B. \ 2H_2 + O_2 \rightarrow 2H_2O & \text{II. Fusion with +ve Q value} \\ \hline C. \ ^3_1 H + ^2_1 H \rightarrow ^4_2 He + n & \text{III. Fission} \\ \hline D. \ ^1_1 H + ^3_1 H \rightarrow ^4_2 H + \gamma & \text{IV. Fusion with -ve Q value} \\ \hline \end{array} \]
Choose the correct answer from the options given below:
Match List - I with List - II.