Question:
From the figure, \(θ=\)
From the figure, \(θ=\)
Updated On: Apr 30, 2024
- 45°
- 60°
- 30°
- 75°
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The correct option is (B): 60°
Was this answer helpful?
0
0
Top Questions on Trigonometric Ratios of Some Specific Angles
- State whether the following are true or false. Justify your answer.
(i) sin (A + B) = sin A + sin B.
(ii) The value of sin \(\text{θ}\) increases as \(\text{θ}\) increases.
(iii) The value of cos \(\text{θ}\) increases as \(\text{θ}\) increases.
(iv) sin \(\text{θ}\) = cos \(\text{θ}\) for all values of \(\text{θ}\).
(v) cot A is not defined for A = 0°- CBSE Class X
- Mathematics
- Trigonometric Ratios of Some Specific Angles
- If tan (A + B) = \(\sqrt3\) and tan (A - B) = \(\frac{1}{\sqrt3}\); 0°\( <\) (A + B) \(≤\) 90° ; A > B, find A and B
- CBSE Class X
- Mathematics
- Trigonometric Ratios of Some Specific Angles
- Choose the correct option and justify your choice: \(\frac{2\ tan\ 30°}{1 - tan^2 30°} =\)
- CBSE Class X
- Mathematics
- Trigonometric Ratios of Some Specific Angles
- Choose the correct option and justify your choice: sin 2A = 2 sin A is true when A =
- CBSE Class X
- Mathematics
- Trigonometric Ratios of Some Specific Angles
- Choose the correct option and justify your choice: \(\frac{1 - tan^2 45°}{1 + tan^2 45°} =\)
- CBSE Class X
- Mathematics
- Trigonometric Ratios of Some Specific Angles
View More Questions
Questions Asked in TS POLYCET exam
- The value of \(\tan 26^\circ. \tan 64^\circ\) is
- TS POLYCET - 2023
- Trigonometry
- When white light is incident on a glass prism, the least deviated colour is
- TS POLYCET - 2023
- Wave Optics
- If 5x+py+8=0 and 10x+15y+12=0 has no solution, then p =
- TS POLYCET - 2023
- Quadratic Equations
- If \(\sec \theta = \frac{2}{\sqrt{3}}\),then \(cosθ=\)
- TS POLYCET - 2023
- Trigonometry
- In the figure, if AP and AQ are the two tangents to a circle with centre 'O' so that \(∠OQP=15°\), then \(∠QAP=\)
- TS POLYCET - 2023
- Tangent to a Circle
View More Questions