For x ∈ (0, π), the equation sin x + 2sin2x −sin3x = 3 has
For x ∈ (0, π), the equation sin x + 2sin2x −sin3x = 3 has
Infinitely many solutions
Three solutions
One solution
No solution
The Correct Option is D
Solution and Explanation
The correct answer is option D) No solution
The least value of R.H.S is 3 at x = π/2 while the greatest value of L.H.S is 3 at x = π/3.
Hence, L.H.S and R.H.S are not equal at the same value of x. so, no solution
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and
\[ 2\cos^2\theta - 3\sin\theta = 0 \]
is two.
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in \( [0, \pi] \) is two.
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