Question:

Prove that: \[ \frac{\cos \theta - 2 \cos^3 \theta}{\sin \theta - 2 \sin^3 \theta} + \cot \theta = 0 \]

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Factor cubic terms and use \(\sin^2 \theta + \cos^2 \theta = 1\) identity to simplify expressions.
Updated On: May 20, 2025
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Solution and Explanation

Factor numerator and denominator: \[ = \frac{\cos \theta (1 - 2 \cos^2 \theta)}{\sin \theta (1 - 2 \sin^2 \theta)} + \cot \theta \] Use identity: \[ 1 - 2 \cos^2 \theta = - (1 - 2 \sin^2 \theta) \] Simplify, and sum terms to prove zero.
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