The correct order of set of reagents for the above conversion is :
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Electrophilic aromatic substitution of amines typically requires the use of halogenating agents like Br\(_2\), activated by FeBr\(_3\), and an appropriate base like NaOH for the reaction to proceed smoothly.
The given reaction represents the bromination of an amine group, likely to form an amine derivative, with Br\(_2\) under the influence of a Lewis acid such as FeBr\(_3\), and the reaction is carried out in the presence of NaOH to neutralize the acids formed. The major product obtained in this process follows electrophilic aromatic substitution.
Final Answer: Option (1).
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Approach Solution -2
Step 1: Analyze the given reaction.
The reaction involves the conversion of an aniline (C6H5NH2) into 2-bromoaniline (C6H4BrNH2). This is an example of a bromination reaction where the amino group (-NH2) is substituted by a bromine atom (Br) at the ortho position on the benzene ring.
Step 2: Identify the reagents and their roles.
- Br2 (Bromine): Bromine is the electrophile that will react with the benzene ring. In the presence of a catalyst, bromine will substitute a hydrogen atom on the ring with a bromine atom.
- FeBr3 (Ferric bromide): FeBr3 is a Lewis acid and acts as a catalyst for the electrophilic aromatic substitution reaction. It helps in the generation of the bromine electrophile (Br+).
- H2O (with heat): The presence of water and heat will help in the hydrolysis process after the substitution, ensuring the formation of the major product.
- NaOH: Sodium hydroxide is used to neutralize any acidic intermediates and to help in the final step to remove any unwanted byproducts.
Step 3: Conclusion.
The correct order of reagents for the given conversion is: \( \text{Br}_2, \text{FeBr}_3, \text{H}_2\text{O}(\Delta), \text{NaOH} \).
Final Answer:
\[
\boxed{\text{Br}_2, \text{FeBr}_3, \text{H}_2\text{O}(\Delta), \text{NaOH}}.
\]
