Question:

For a spontaneous process at constant temperature and pressure, which of the following is true?

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For a spontaneous process at constant temperature and pressure, the correct thermodynamic condition is: \[ \Delta G = \Delta H - T\Delta S<0. \] This indicates the process proceeds with a decrease in free energy.
Updated On: Jun 3, 2025
  • \( \Delta G>0 \)
  • \( \Delta H>0 \)
  • \( \Delta G<0 \)
  • \( \Delta S<0 \)
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The Correct Option is C

Solution and Explanation

Step 1: Use Gibbs free energy criteria.
For a process to be spontaneous at constant temperature and pressure, the change in Gibbs free energy must be negative, i.e., \[ \Delta G<0. \]
Step 2: Evaluate other options.
\( \Delta G>0 \): Implies non-spontaneous process.
\( \Delta H>0 \): Possible, but does not guarantee spontaneity.
\( \Delta S<0 \): May occur, but not a definitive condition for spontaneity.
\( \Delta G<0 \): This is the correct condition for spontaneity.
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