Question:

Five charges +q, +5q, –2q, +3q and –4q are situated as shown in the figure. The electric flux due to this configuration through the surface S is
charges

Updated On: Dec 17, 2024
  • 5qϵ0 \frac{5q}{\epsilon_0}
  • 4qϵ0 \frac{4q}{\epsilon_0}
  • 3qϵ0 \frac{3q}{\epsilon_0}
  • qϵ0 \frac{q}{\epsilon_0}
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The Correct Option is B

Solution and Explanation

According to Gauss’s law, the electric flux Φ through a closed surface is given by:

Φ=qinϵ0Φ = \frac{q_{in}}{\epsilon_0},

where qin is the total charge enclosed by the surface.

In this problem, the charges enclosed by the surface are qin=q+(2q)+5q=4qq_{in} = q + (-2q) + 5q = 4q.

Thus, the electric flux is:

Φ=4qϵ0Φ = \frac{4q}{\epsilon_0}.

The correct answer is Option (2).

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