Find the distance from the point \( A(2, 3, -1) \) to the given straight lines \( 2x - 2y + z + 3 = 0 \) and \( 3x - 2y + 2z + 17 = 0 \).
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The distance from a point \( (x_1, y_1, z_1) \) to a plane \( ax + by + cz + d = 0 \) is given by:
\[
{Distance} = \frac{|ax_1 + by_1 + cz_1 + d|}{\sqrt{a^2 + b^2 + c^2}}
\]
Using the distance formula from a point to a plane, we calculate the distance from the point \( A(2, 3, -1) \) to the two planes. The distance to the first plane is \( \frac{6}{\sqrt{5}} \) units.