Question

Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.

Answer 1

Let OACB be a sector of the circle making 60° angle at centre O of the circle.

Area of sector of angle θ =\( \frac{θ }{ 360 ^{\degree}} \times πr^2\)

 Area of sector OACB =\( \frac{60^{\degree}}{360^{\degree}} \times \frac{22}{7} \times (6)^2\)

=\( \frac{1}{6 }\times \frac{22}{7} \times6 \times 6 = \frac{132}{ 7} cm^2\)

Therefore, the area of the sector of the circle making 60° at the centre of the circle is \(\frac{132}{ 7} cm^2\).