Fig.
If the initial pressure of a gas 0.03 atm, the mass of the gas absorbed per gram of the adsorbent is ____× 10–2g
If the initial pressure of a gas 0.03 atm, the mass of the gas absorbed per gram of the adsorbent is ____× 10–2g
Correct Answer: 12
Solution and Explanation
The correct answer is 12
Given that log K = intercept = 0.602 = log 4
∴ K = 4
Slope \(=\frac{1}{n}=1\) and
initial pressure = 0.03 atm
\(\frac{x}{m}=K(p)^{\frac{1}{n}} \)
= 4 × 0.03 = 0.12 = 12 × 10–2
∴ mass of gas absorbed per gm of adsorbent = 12 × 10–2 g
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Concepts Used:
Adsorption
Heinrich Kayser, the German physicist was the first to coin the term adsorption. Adsorption can be explained as a surface phenomenon where particles remain attached on the top of a material. Generally, it comprises the molecules, atoms, liquid, solid in a dissolved stage, even the ions of a gas that are attached to the surface. Much to our surprise, the consequence of surface energy i.e. adsorption is present in biological, physical, chemical, and natural systems and are used in many industrial applications.
