For a non-rigid diatomic molecule, the degrees of freedom \( f \) are given by:
\[f = 5 + 2(3N - 5)\]
Since \( N = 2 \) (for diatomic molecules):
\[f = 5 + 2(3 \times 2 - 5) = 7\]
The energy of one molecule is:
\[\text{Energy} = \frac{f}{2} k_B T = \frac{7}{2} k_B T\]
For 10 molecules, the total energy is:
\[10 \times \frac{7}{2} k_B T = 35 k_B T\]
Let \[ I(x) = \int \frac{dx}{(x-11)^{\frac{11}{13}} (x+15)^{\frac{15}{13}}} \] If \[ I(37) - I(24) = \frac{1}{4} \left( b^{\frac{1}{13}} - c^{\frac{1}{13}} \right) \] where \( b, c \in \mathbb{N} \), then \[ 3(b + c) \] is equal to:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).