Question:

Energy of 10 non rigid diatomic molecules at temperature T is :

Updated On: Mar 22, 2025
  • $\frac{7}{2} \, RT$
  • $70 \, K_B T$
  • $35 \, RT$
  • $35 \, K_B T$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

For a non-rigid diatomic molecule, the degrees of freedom \( f \) are given by:
\[f = 5 + 2(3N - 5)\]
Since \( N = 2 \) (for diatomic molecules):
\[f = 5 + 2(3 \times 2 - 5) = 7\]
The energy of one molecule is:
\[\text{Energy} = \frac{f}{2} k_B T = \frac{7}{2} k_B T\]
For 10 molecules, the total energy is:
\[10 \times \frac{7}{2} k_B T = 35 k_B T\]

Was this answer helpful?
0
0

Questions Asked in JEE Main exam

View More Questions