Question:
The internal energy of one mole of a rigid diatomic gas at absolute temperature \( T \) is:
The internal energy of one mole of a rigid diatomic gas at absolute temperature \( T \) is:
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For rigid diatomic gases, the degrees of freedom are 5 (3 translational + 2 rotational), leading to:
\[
U = \frac{5}{2} nRT
\]
Updated On: Jun 5, 2025
- \( 3RT \)
- \( \frac{5}{2} RT \)
- \( \frac{3}{2} RT \)
- \( \frac{1}{2} RT \)
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The Correct Option is B
Solution and Explanation
The internal energy of a gas is given by:
\[
U = \frac{f}{2} nRT
\]
For one mole (\( n = 1 \)) of a rigid diatomic gas, only translational and rotational degrees of freedom contribute. The degree of freedom for such a gas is:
\[
f = 5
\]
Thus, the internal energy is:
\[
U = \frac{5}{2} RT
\]
Conclusion
Thus, the correct answer is:
\[
\frac{5}{2} RT
\]
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