Question:
If the rms speed of the molecules of a diatomic gas at a temperature of 322K is 2000 m/s, then the gas is
If the rms speed of the molecules of a diatomic gas at a temperature of 322K is 2000 m/s, then the gas is
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For identifying gases based on rms speed, use the formula \( v_{rms} = \sqrt{\frac{3kT}{M}} \), where the lighter gases like hydrogen will have higher rms speeds.
Updated On: July 22, 2025
- hydrogen
- nitrogen
- oxygen
- chlorine
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The Correct Option is A
Solution and Explanation
The rms speed \( v_{rms} \) is related to the temperature \( T \) and molar mass \( M \) of the gas by the formula \( v_{rms} = \sqrt{\frac{3kT}{M}} \). Substituting the given values, we find that hydrogen, with its low molar mass, matches the given rms speed.
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