For borax bead test:
• In the oxidizing flame, metal ions form metaborates, which produce characteristic colours.
• The observed colour is a key indicator of the specific metal ion present.
\(Cu(BO_2)_2\)
\(Cu_3B_2\)
Borax Bead Test:
1. Definition: The borax bead test is a qualitative test used to identify metal ions based on the colour imparted to the bead in the oxidizing or reducing flame.
In this test, borax (\(\text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O}\)) decomposes to form sodium metaborate (\(\text{NaBO}_2\)) and boric anhydride (\(\text{B}_2\text{O}_3\)) when heated:
\[\text{Na}_2\text{B}_4\text{O}_7 \xrightarrow{\Delta} 2\text{NaBO}_2 + \text{B}_2\text{O}_3.\]
2. Reaction with \(\text{CuSO}_4\): Copper ions react with boric anhydride (\(\text{B}_2\text{O}_3\)) to form copper metaborate (\(\text{Cu(BO}_2)_2\)) in the oxidizing flame:
\[\text{CuSO}_4 + \text{B}_2\text{O}_3 \rightarrow \text{Cu(BO}_2)_2 + \text{SO}_3.\]
3.Observation: \(\text{Cu(BO}_2)_2\) is responsible for the blue-green colour observed in the oxidizing flame.
Final Answer: \((3)\) \(\mathbf{Cu(BO}_2)_2\).
Observe the following data given in the table. (\(K_H\) = Henry's law constant)
| Gas | CO₂ | Ar | HCHO | CH₄ |
|---|---|---|---|---|
| \(K_H\) (k bar at 298 K) | 1.67 | 40.3 | \(1.83 \times 10^{-5}\) | 0.413 |
The correct order of their solubility in water is
Match List I with List II:
Choose the correct answer from the options given below:
In the circuit shown, assuming the threshold voltage of the diode is negligibly small, then the voltage \( V_{AB} \) is correctly represented by:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: