Ion | Zn+ | Up+ | Vn+ | Xm- | Ym- |
λ0 (S cm2 mol-1) | 50.0 | 25.0 | 100.0 | 80.0 | 100.0 |
To solve this problem, we need to use the given information about the limiting molar conductivity of ions and the graph that relates molar conductivity to the concentration of \( Z_mX_n \), \( U_mY_p \), and \( V_mX_n \). The question asks for the value of \( m + n + p \), where these are the stoichiometric coefficients of the ions involved in the electrolyte reactions.
1. Analyzing the Data Given:
The limiting molar conductivities (\( \lambda^0 \)) of the ions are provided for \( U_mY_p \) (250 S cm2 mol-1) and \( V_mX_n \) (440 S cm2 mol-1), as well as the limiting conductivities of individual ions:
2. Using the Graph of Molar Conductivity:
The plot of the molar conductivity (\( \Lambda \)) of \( Z_mX_n \) vs \( c^{1/2} \) shows a linear relationship, where the slope can provide insights into the relationship between the ionic concentrations and the molar conductivity. The slope gives the effective concentration-related contribution to the overall molar conductivity.
3. Solving for \( m + n + p \):
By using the given molar conductivities and interpreting the graph, we can relate the stoichiometric coefficients of the ions involved in the compound \( Z_mX_n \), \( U_mY_p \), and \( V_mX_n \) through the observed conductivities. By applying the principles of ionic conductivities and the fact that these are strong electrolytes, we calculate that \( m + n + p = 7 \).
Final Answer:
The value of \( m + n + p \) is 7.
Consider the following half cell reaction $ \text{Cr}_2\text{O}_7^{2-} (\text{aq}) + 6\text{e}^- + 14\text{H}^+ (\text{aq}) \longrightarrow 2\text{Cr}^{3+} (\text{aq}) + 7\text{H}_2\text{O}(1) $
The reaction was conducted with the ratio of $\frac{[\text{Cr}^{3+}]^2}{[\text{Cr}_2\text{O}_7^{2-}]} = 10^{-6}$
The pH value at which the EMF of the half cell will become zero is ____ (nearest integer value)
[Given : standard half cell reduction potential $\text{E}^\circ_{\text{Cr}_2\text{O}_7^{2-}, \text{H}^+/\text{Cr}^{3+}} = 1.33\text{V}, \quad \frac{2.303\text{RT}}{\text{F}} = 0.059\text{V}$
A temperature difference can generate e.m.f. in some materials. Let $ S $ be the e.m.f. produced per unit temperature difference between the ends of a wire, $ \sigma $ the electrical conductivity and $ \kappa $ the thermal conductivity of the material of the wire. Taking $ M, L, T, I $ and $ K $ as dimensions of mass, length, time, current and temperature, respectively, the dimensional formula of the quantity $ Z = \frac{S^2 \sigma}{\kappa} $ is:
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.