Consider the reaction:
Fe203(s) + 3CO(g) = 2Fe(s) + 3CO2(g)
Which of the following will not affect the equilibrium state:
(I) Addition of Fe2O3
(II) Addition of CO2
(III) Decreasing mass of Fe2O3
(IV) Removal of CO
Fe203(s) + 3CO(g) = 2Fe(s) + 3CO2(g)
Which of the following will not affect the equilibrium state:
(I) Addition of Fe2O3
(II) Addition of CO2
(III) Decreasing mass of Fe2O3
(IV) Removal of CO
- (II) and (IV)
- (I) and (IV)
- (I) and (III)
- All will affect the equilibrium
The Correct Option is C
Solution and Explanation
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