Question

Consider the above reaction, what mass of CaCl₂ will be formed if 250 ml of 0.76 M HCl reacts with 1000 g of CaCO₃?

• A. 3.908 g
• B. 2.636 g
• C. 10.545 g
• D. 5.272 g

Hint:

In stoichiometry, make sure the balanced chemical equation is used to relate the moles of reactants and products. Converting moles to grams requires using the molar mass.

Answer 1

The Correct Option is C

Using stoichiometry, the moles of \( \text{CaCO}_3 \) are calculated: \[ \text{Moles of CaCO}_3 = \frac{1000}{100} = 10 \, \text{mol} \] Now, for the reaction: \[ \text{CaCO}_3 + 2\text{HCl} \rightarrow \text{CaCl}_2 + \text{CO}_2 + \text{H}_2\text{O} \] Hence, the moles of \( \text{CaCl}_2 \) formed will be \( 10 \, \text{mol} \). Finally: \[ \text{Mass of CaCl}_2 = 10.545 \, \text{g} \]