




The reaction proceeds via an \( S_N1 \) mechanism where the chlorine group leaves, forming a carbocation.
After the formation of the carbocation, a 1,2-hydride shift occurs to stabilize the carbocation, resulting in a more stable tertiary carbocation.
Subsequent attack by hydroxide ion (\( \text{OH}^- \)) leads to the formation of the major product:
The major product is a tertiary alcohol.
The colour of the solution observed after about 1 hour of placing iron nails in copper sulphate solution is:
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 