The correct answer is option (C): a,b,c cannot be in A.P. or G.P. but can be in H.P.
In \(ax^2+bx+c\), d should be less than 0.
So, \(4b^2-4ac=0\)
\(\Rightarrow\)\(b^2-ac=0\)
Putting the values of \(b=a+\frac{c}{2}\) for A.P,(ac)\(^{\frac{1}{2}}\) for G.P and \(\frac{2ac}{a+c}\) for H.P, we get the above condition only satisfies H.P.
\( \text{M} \xrightarrow{\text{CH}_3\text{MgBr}} \text{N} + \text{CH}_4 \uparrow \xrightarrow{\text{H}^+} \text{CH}_3\text{COCH}_2\text{COCH}_3 \)
Identify the ion having 4f\(^6\) electronic configuration.
A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers.
Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.
The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)
Read More: Nature of Roots of Quadratic Equation