Question:

Consider a quadratic equation ax2+2bx+c=0 where a,b,c are positive real numbers. If the equation has no real root, then which of the following is true?

Updated On: Apr 1, 2025
  • a,b,c cannot be in A.P. or H.P. but can be in G.P.
  • a,b,c cannot be in G.P. or H.P. but can be in A.P.
  • a,b,c cannot be in A.P. or G.P. but can be in H.P.
  • a,b,c cannot be in A.P.,G.P or H.P. 
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The Correct Option is C

Approach Solution - 1

The correct answer is option (C): a,b,c cannot be in A.P. or G.P. but can be in H.P.

In  \(ax^2+bx+c\), d should be less than 0.

So, \(4b^2-4ac=0\)

\(\Rightarrow\)\(b^2-ac=0\)

Putting  the values of \(b=a+\frac{c}{2}\) for A.P,(ac)\(^{\frac{1}{2}}\) for G.P and \(\frac{2ac}{a+c}\) for H.P, we get the above condition only satisfies H.P.

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Approach Solution -2

The correct answer is option (C): a, b, c cannot be in A.P. or G.P. but can be in H.P.
For the quadratic expression ax2 + bx + c, the discriminant d should be less than 0.
So, 4b2 - 4ac = 0
This simplifies to: b2 = ac
Now, let's put the values of b for different progressions:
For Arithmetic Progression (A.P): b = a + c/2
For Geometric Progression (G.P): b = (ac)1/2
For Harmonic Progression (H.P): b = 2ac / (a + c)
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Concepts Used:

Quadratic Equations

A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers

Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.

The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)

Two important points to keep in mind are:

  • A polynomial equation has at least one root.
  • A polynomial equation of degree ‘n’ has ‘n’ roots.

Read More: Nature of Roots of Quadratic Equation

There are basically four methods of solving quadratic equations. They are:

  1. Factoring
  2. Completing the square
  3. Using Quadratic Formula
  4. Taking the square root