Consider a block and trolley system as shown in figure. If the coefficient of kinetic friction between the trolley and the surface is 0.04, the acceleration of the system in m/s2 is : (Consider that the string is massless and unstretchable and the pulley is also massless and frictionless) :
The kinetic frictional force is given by:
\[ f_k = \mu N = 0.04 \times 20g = 8 \, \text{Newton} \]
The net force acting on the system is:
\[ F_{\text{net}} = 60 \, \text{N} - f_k = 60 - 8 = 52 \, \text{N} \]
The total mass of the system is:
\[ m_{\text{total}} = 20 \, \text{kg} + 6 \, \text{kg} = 26 \, \text{kg} \]
The acceleration of the system is:
\[ a = \frac{F_{\text{net}}}{m_{\text{total}}} = \frac{52}{26} = 2 \, \text{ms}^{-2} \]
Two blocks of masses m and M, (M > m), are placed on a frictionless table as shown in figure. A massless spring with spring constant k is attached with the lower block. If the system is slightly displaced and released then ($ \mu $ = coefficient of friction between the two blocks)
The correct stability order of the following species/molecules is: