8 kg
The forces acting on the body are: 1. The tension \( T \) in the rope, which acts upwards. 2. The weight of the body \( W = mg \), which acts downwards. 3. The force due to the acceleration of the lift \( F = ma \), where \( a = 0.2 \, \text{m/s}^2 \) is the acceleration of the lift.
The net force on the body is the difference between the upward tension and the downward weight, and it equals the mass times the acceleration of the lift: \[ T - mg = ma \] Substitute the known values: \[ 80 - m(9.8) = m(0.2) \] Simplify the equation: \[ 80 = m(9.8 + 0.2) \] \[ 80 = m(10) \] \[ m = \frac{80}{10} = 8 \, \text{kg} \]
Thus, the mass of the body is \( 8 \, \text{kg} \).
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is