8 kg
The forces acting on the body are: 1. The tension \( T \) in the rope, which acts upwards. 2. The weight of the body \( W = mg \), which acts downwards. 3. The force due to the acceleration of the lift \( F = ma \), where \( a = 0.2 \, \text{m/s}^2 \) is the acceleration of the lift.
The net force on the body is the difference between the upward tension and the downward weight, and it equals the mass times the acceleration of the lift: \[ T - mg = ma \] Substitute the known values: \[ 80 - m(9.8) = m(0.2) \] Simplify the equation: \[ 80 = m(9.8 + 0.2) \] \[ 80 = m(10) \] \[ m = \frac{80}{10} = 8 \, \text{kg} \]
Thus, the mass of the body is \( 8 \, \text{kg} \).
Two blocks of masses m and M, (M > m), are placed on a frictionless table as shown in figure. A massless spring with spring constant k is attached with the lower block. If the system is slightly displaced and released then ($ \mu $ = coefficient of friction between the two blocks)