1 N
We are given the following: - Mass of the body \( m = 200 \, \text{g} = 0.2 \, \text{kg} \) - Change in velocity \( \Delta v = 25 \, \text{m/s} \) - Time \( t = 5 \, \text{seconds} \) The force required to change the velocity is given by Newton's second law: \[ F = \frac{m \Delta v}{t} \] Substituting the values: \[ F = \frac{0.2 \times 25}{5} = \frac{5}{5} = 1 \, \text{N} \]
Thus, the correct force required is \( 1 \, \text{N} \).
Two blocks of masses m and M, (M > m), are placed on a frictionless table as shown in figure. A massless spring with spring constant k is attached with the lower block. If the system is slightly displaced and released then ($ \mu $ = coefficient of friction between the two blocks)