Question:

Choose the most appropriate options. Let \( P = \{ \theta : \sin \theta - \cos \theta = \sqrt{2} \cos \theta \} \) and \( Q = \{ \theta : \sin \theta + \cos \theta = \sqrt{2} \sin \theta \} \). Then,

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Always check the conditions for the set relationships before concluding about inclusion or equality.
Updated On: Apr 1, 2025
  • \( P \subset Q \) and \( Q - P \neq \emptyset \)
  • \( Q \not\subset P \)
  • \( P \not\subset Q \)
  • \( P = Q \)
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The Correct Option is D

Solution and Explanation

After solving the equations for \( P \) and \( Q \), we find that both sets are equivalent. Hence, \( P = Q \).
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