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Guru Gobind Singh Indraprastha University Common Entrance Test
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Mathematics
List of top Mathematics Questions on Calculus asked in Guru Gobind Singh Indraprastha University Common Entrance Test
Negation of the statement
(
ρ
∧
r
)
→
(
r
∨
q
)
(\rho \land r) \rightarrow (r \lor q)
(
ρ
∧
r
)
→
(
r
∨
q
)
is
IPU CET - 2018
IPU CET
Mathematics
Calculus
Evaluate the limit:
lim
x
→
a
log
(
x
a
−
1
)
x
−
a
\lim_{x \to a} \frac{\log{(x^{a-1})}}{x-a}
x
→
a
lim
x
−
a
lo
g
(
x
a
−
1
)
IPU CET - 2018
IPU CET
Mathematics
Calculus
Find the limit
lim
x
→
0
(
1
+
tan
2
x
)
3
/
x
\lim_{x \to 0} \left( 1 + \tan^2 \sqrt{x} \right)^{3/x}
x
→
0
lim
(
1
+
tan
2
x
)
3/
x
IPU CET - 2018
IPU CET
Mathematics
Calculus
Find the area of the figure bounded by the parabola
y
2
=
4
x
y^2 = 4x
y
2
=
4
x
and
x
2
=
4
y
x^2 = 4y
x
2
=
4
y
.
IPU CET - 2018
IPU CET
Mathematics
Calculus
The value of
∫
0
π
2
e
x
cos
x
d
x
\int_0^{\frac{\pi}{2}} e^x \cos x \, dx
∫
0
2
π
e
x
cos
x
d
x
is equal to:
IPU CET - 2018
IPU CET
Mathematics
Calculus
Choose the most appropriate options.
Let
P
=
{
θ
:
sin
θ
−
cos
θ
=
2
cos
θ
}
P = \{ \theta : \sin \theta - \cos \theta = \sqrt{2} \cos \theta \}
P
=
{
θ
:
sin
θ
−
cos
θ
=
2
cos
θ
}
and
Q
=
{
θ
:
sin
θ
+
cos
θ
=
2
sin
θ
}
Q = \{ \theta : \sin \theta + \cos \theta = \sqrt{2} \sin \theta \}
Q
=
{
θ
:
sin
θ
+
cos
θ
=
2
sin
θ
}
. Then,
IPU CET - 2018
IPU CET
Mathematics
Calculus
The series
1
+
1
+
3
2
2
+
4
2
3
+
5
2
4
+
⋯
1 + 1 + \frac{3}{2^2} + \frac{4}{2^3} + \frac{5}{2^4} + \cdots
1
+
1
+
2
2
3
+
2
3
4
+
2
4
5
+
⋯
is equal to
IPU CET - 2018
IPU CET
Mathematics
Calculus
The value of the integral
∫
−
3
5
∣
x
−
3
∣
d
x
\int_{-3}^{5} |x - 3| \, dx
∫
−
3
5
∣
x
−
3∣
d
x
is
IPU CET - 2018
IPU CET
Mathematics
Calculus
Choose the most appropriate option.
∫
−
2
2
3
x
7
−
2
x
5
+
x
3
−
3
x
4
+
3
x
2
+
1
d
x
\int_{-2}^{2} \frac{3x^7 - 2x^5 + x^3 - 3}{x^4 + 3x^2 + 1} \, dx
∫
−
2
2
x
4
+
3
x
2
+
1
3
x
7
−
2
x
5
+
x
3
−
3
d
x
IPU CET - 2018
IPU CET
Mathematics
Calculus