During titration of a weak acid with a strong base, the conductance increases due to the formation of a salt and further ionization of the strong base.
During the titration of a weak acid (benzoic acid) with a strong base (NaOH):
• Initially, the conductance is low because benzoic acid is a weak electrolyte and does not fully ionize in water.
• As NaOH is added, benzoic acid reacts to form the sodium benzoate salt, which is highly ionized, increasing the conductance.
• After the equivalence point, the excess NaOH contributes additional OH− ions, further increasing the conductance.
Option (2) represents this behavior correctly.
The correct answer is (C) :
(A) → (B) Free \(H^+\) ions are replaced by \(Na^⊕\) which decreases conductance.
(B) → (C) Un-dissociated benzoic acid reacts with \(NaOH\) and forms salt which increases ions & conductance increases.
(C) → (D) After equivalence point at (3), \(NaOH\) added further increases \(Na^⊕\) & \(OH^⊙\) ions which further increases the conductance.
Following figure shows dependence of molar conductance of two electrolytes on concentration. Λo m is the limiting molar conductivity. The number of incorrect statement(s) from the following is ________
(A) \(\Lambda \text{o m}\) for electrolyte A is obtained by extrapolation.
(B) For electrolyte B, \(\Lambda \text{m}\) vs \(\sqrt c\) graph is a straight line with intercept equal to o \(\Lambda \text{m}\)
(C) At infinite dilution, the value of degree of dissociation approaches zero for electrolyte B.
(D) Λo m for any electrolyte A or B can be calculated using \(\lambda0\) for individual ions.
An electrochemical cell is a device that is used to create electrical energy through the chemical reactions which are involved in it. The electrical energy supplied to electrochemical cells is used to smooth the chemical reactions. In the electrochemical cell, the involved devices have the ability to convert the chemical energy to electrical energy or vice-versa.