Question:

Find pH of the solution if \([H^+] = 2 \times 10^{-4} \, \text{mol/L}\)

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For pH calculations, remember that \( \log(10^{-x}) = -x \) and \( \log(2) \approx 0.3010 \). This can help simplify calculations.
Updated On: Apr 25, 2025
  • 3.5
  • 4.5
  • 5.5
  • 6.5
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The Correct Option is B

Solution and Explanation


The pH of a solution is given by the formula: \[ \text{pH} = -\log[H^+] \] Substitute the given value of \( [H^+] = 2 \times 10^{-4} \, \text{mol/L} \): \[ \text{pH} = -\log(2 \times 10^{-4}) \] Using logarithmic properties: \[ \text{pH} = -\log(2) - \log(10^{-4}) = -0.3010 + 4 = 4.5 \] Thus, the pH of the solution is \( 4.5 \).
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