Analyzing Statement-I:
We are given:
\(\mathbf{a} = \hat{i} + 2\hat{j} - 3\hat{k}\), \(\mathbf{b} = 2\hat{i} + \hat{j} - \hat{k}\)
We are looking for a vector \(\mathbf{r}\) satisfying two conditions: 1. \(\mathbf{a} \times \mathbf{r} = \mathbf{a} \times \mathbf{b}\) 2. \(\mathbf{a} \cdot \mathbf{r} = 0\)
Step 1: Find \(\mathbf{a} \times \mathbf{b}\).
The cross product \(\mathbf{a} \times \mathbf{b}\) is calculated as follows:
\[
\mathbf{a} \times \mathbf{b} =
\begin{vmatrix}
\hat{i} & \hat{j} & \hat{k} \\
1 & 2 & -3 \\
2 & 1 & -1
\end{vmatrix}
\]
Expanding the determinant:
\[
\mathbf{a} \times \mathbf{b} = \hat{i} \left(2(-3) - (1)(-1)\right) - \hat{j} \left(1(-1) - 2(-1)\right) + \hat{k} \left(1(1) - 2\right)
\]
\[
\mathbf{a} \times \mathbf{b} = \hat{i}(2 - (-3)) - \hat{j}(1 - (-6)) + \hat{k}(1 - 4)
\]
\[
\mathbf{a} \times \mathbf{b} = 5\hat{i} - 5\hat{j} - 3\hat{k}
\]
Thus, \(\mathbf{a} \times \mathbf{b} = 5\hat{i} - 5\hat{j} - 3\hat{k}\).
Step 2: Solve \(\mathbf{a} \times \mathbf{r} = \mathbf{a} \times \mathbf{b}\).
The vector \(\mathbf{r}\) must satisfy \(\mathbf{a} \times \mathbf{r} = 5\hat{i} - 5\hat{j} - 3\hat{k}\). We can find \(\mathbf{r}\) by using the conditions on \(\mathbf{r}\), but after solving, it turns out that the magnitude of \(\mathbf{r}\) does not match the given value \(\sqrt{10}\).
Thus, Statement-I is incorrect.
Analyzing Statement-II:
We are given a triangle ABC with the inequality:
\[
\cos 2A + \cos 2B + \cos 2C \geq -\frac{3}{2}
\]
This is a known trigonometric inequality for the angles of a triangle. By using standard trigonometric identities and properties of angles in a triangle, it is established that:
\[
\cos 2A + \cos 2B + \cos 2C \geq -\frac{3}{2}
\]
Thus, Statement-II is correct.
Conclusion:
Since Statement-I is incorrect and Statement-II is correct, the correct answer is:
Answer: (2) Statement-I is incorrect but Statement-II is correct.
A vector has magnitude same as that of A = \(-3\hat{i} + 4\hat{j}\) and is parallel to B = \(4\hat{i} + 3\hat{j}\). The x and y components of this vector in the first quadrant are x and y respectively where:
\(x = \_\_\_\_\).