To understand the given statements, let's analyze both the assertion and the reason:
Conclusion:
Thus, the correct answer is: Both A and R are true and R is the correct explanation of A.
As the atomic number increases then the potential energy of electrons present in same shell becomes more and more negative. And therefore total energy also becomes more negative.
\(E_{total} = -13.6 \frac{z^2}{n^2}eV\)
∴ Energies of the orbitals in the same subshell decreases with increase in atomic number.
The correct answer is (A): Both A and R are true and R is the correct explanation of A
List-I ( Ions ) | List-II ( No. of unpaired electrons ) | ||
| A | Zn$^{2+}$ | (I) | 0 |
| B | Cu$^{2+}$ | (II) | 4 |
| C | Ni$^{2+}$ | (III) | 1 |
| D | Fe$^{2+}$ | (IV) | 2 |
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
Electron Configuration is referred to as the distribution of electrons in an atom's orbitals. An electron in an atom is defined by a set of four quantum numbers (n), the most important of which defines the main energy level known as a shell. The filling of electrons into different subshells, also known as orbitals (s, p, d, f) in an atom. The position of an element in the periodic table is determined by the quantum numbers of the last orbital filled.