The energy of an electron in the ground state (n=1) for He+ ion is -xJ, then that for an electron in n=2 state for Be3+ ion in J is:
- -x
- \(-\frac{x}{9}\)
- -4x
- \(-\frac{4}{9}x\)
The Correct Option is A
Solution and Explanation
Correct option is (1) -x
En = -RH (Z2 / n2) J
For He+ (n = 1), En = -x = -RH (22 / 12) = -4RH
∴ RH = x / 4
For Be3+ (n = 2), En = -RH (Z2 / n2) J
= - (x / 4) × (4 × 4 / 2 × 2) = -x J
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