Question:

The energy of an electron in the ground state (n=1) for He+ ion is -xJ, then that for an electron in n=2 state for Be3+ ion in J is:

Updated On: Mar 26, 2025
  • -x
  • \(-\frac{x}{9}\)
  • -4x
  • \(-\frac{4}{9}x\)
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The Correct Option is A

Solution and Explanation

Correct option is (1) -x

En = -RH (Z2 / n2) J

For He+ (n = 1), En = -x = -RH (22 / 12) = -4RH

∴ RH = x / 4

For Be3+ (n = 2), En = -RH (Z2 / n2) J

= - (x / 4) × (4 × 4 / 2 × 2) = -x J

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