Question:

Match List-I with List-II:

List-I ( Ions )

List-II ( No. of unpaired electrons )

AZn$^{2+}$(I)

0

BCu$^{2+}$(II)

4

CNi$^{2+}$(III)

1

DFe$^{2+}$(IV)

2

Choose the correct answer from the options given below:

Updated On: May 9, 2025
  • (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  • (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  • (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
  • (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
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The Correct Option is C

Approach Solution - 1

The key to solving this problem is to determine the number of unpaired electrons for the given ions. Below is the detailed explanation and matching of List-I with List-II: 

  1. Zn$^{2+}$: Zinc's atomic number is 30, with an electron configuration of [Ar] 3d10 4s2. Zn$^{2+}$ loses two electrons, resulting in a configuration of [Ar] 3d10. Since all electrons in 3d are paired, 0 unpaired electrons. Match: (I).
  2. Cu$^{2+}$: Copper has an atomic number of 29 with a configuration of [Ar] 3d10 4s1. In Cu$^{2+}$, it loses two electrons, resulting in [Ar] 3d9. There is one unpaired electron in the 3d orbital. Match: (III).
  3. Ni$^{2+}$: Nickel has an atomic number of 28, with a configuration of [Ar] 3d8 4s2. In Ni$^{2+}$, it loses two electrons, leading to [Ar] 3d8. It has two unpaired electrons. Match: (IV).
  4. Fe$^{2+}$: Iron has an atomic number of 26 with a configuration of [Ar] 3d6 4s2. Fe$^{2+}$ loses two electrons, resulting in [Ar] 3d6, with four unpaired electrons. Match: (II).

Based on the above analysis, the correct matches are: (A)-(I), (B)-(III), (C)-(IV), (D)-(II).

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Approach Solution -2

1. Zn2+: Electron configuration of Zn is [Ar] 3d10. The ion has 0 unpaired electrons. Therefore, (A) - (I).

2. Cu2+: Electron configuration of Cu is [Ar] 3d10 4s1. The ion has 1 unpaired electron after losing 2 electrons. Therefore, (B) - (III).

3. Ni2+: Electron configuration of Ni is [Ar] 3d8 4s2. The ion has 2 unpaired electrons. Therefore, (C) - (IV).

4. Fe2+: Electron configuration of Fe is [Ar] 3d6 4s2. The ion has 4 unpaired electrons. Therefore, (D) - (II).

Thus, the correct matches are: (A) - (I), (B) - (III), (C) - (IV), (D) - (II).
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