As per the given figure, if $\frac{ dI }{ dt }=-1 A /$ s then the value of $V _{ AB }$ at this instant will be ______$V$

The correct answer is 30.
The differential equation for the circuit is given by:
\[ \frac{dI}{dt} = -1 \ \text{A/sec} \]
The equation for the potential difference across the circuit is:
\[ V_A - IR - L \frac{dI}{dt} - 12 = V_B \]
Substitute \(I = 2 \ \text{A}\), \(R = 12 \ \Omega\), \(L = 6 \ \text{H}\), and \(\frac{dI}{dt} = -1\):
\[ V_A - 2 \times 12 - 6(-1) - 12 = V_B \]
Simplify the equation:
\[ V_A - V_B = 36 - 6 = 30 \ \text{volts} \]
\(V_A - V_B = 30 \ \text{volts}\)
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