Arrange the following in the ascending order of wavelength (\( \lambda \)):
(A) Microwaves (\( \lambda_1 \))
(B) Ultraviolet rays (\( \lambda_2 \))
(C) Infrared rays (\( \lambda_3 \))
(D) X-rays (\( \lambda_4 \)) \text{Choose the most appropriate answer from the options given below:}
In the electromagnetic spectrum, the wavelength (\( \lambda \)) of different types of electromagnetic radiation varies as follows:
- \( \lambda_4 \) (X-rays) have the shortest wavelength.
- \( \lambda_3 \) (Infrared rays) have longer wavelengths than X-rays but shorter than microwaves.
- \( \lambda_1 \) (Microwaves) have longer wavelengths than infrared rays but shorter than ultraviolet rays.
- \( \lambda_2 \) (Ultraviolet rays) have the longest wavelength of all.
Thus, the correct order is: \[ \lambda_4<\lambda_3<\lambda_1<\lambda_2. \]
Final Answer: \( \lambda_4<\lambda_3<\lambda_1<\lambda_2 \).
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: