Question:

The electric field at a point in space is \( 2 \times 10^3 \, \text{N/C} \) and the potential at the same point is \( 100 \, \text{V} \). What is the potential energy of a charge of \( 5 \, \mu\text{C} \) placed at that point?

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Remember: The potential energy of a charge in an electric field is the product of the charge and the electric potential at the point where the charge is located.
Updated On: Jun 4, 2025
  • \( 0.5 \, \text{mJ} \)
  • \( 1.0 \, \text{mJ} \)
  • \( 2.0 \, \text{mJ} \)
  • \( 5.0 \, \text{mJ} \)
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The Correct Option is B

Solution and Explanation

Step 1: Use the formula for potential energy The potential energy \( U \) of a charge \( q \) placed in an electric field is given by the formula: \[ U = qV \] where: - \( q \) is the charge, - \( V \) is the potential at the point. Step 2: Substitute the given values Given: - \( q = 5 \, \mu\text{C} = 5 \times 10^{-6} \, \text{C} \), - \( V = 100 \, \text{V} \). Substitute these values into the formula: \[ U = 5 \times 10^{-6} \times 100 = 5 \times 10^{-4} \, \text{J} = 1.0 \, \text{mJ} \] Answer: Therefore, the potential energy of the charge is \( 1.0 \, \text{mJ} \). So, the correct answer is option (2).
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