The magnification \( m \) produced by a mirror is given by the formula: \[ m = - \frac{v}{u} \] Where:
\( v \) is the image distance,
\( u \) is the object distance.
Given that the image is real and enlarged, the image distance is positive, and the object distance is negative. The condition that the image just touches the pencil means the image and object distances add up to the focal length. Therefore: \[ v + u = f \] Also, the relationship between the focal length \( f \), object distance \( u \), and image distance \( v \) for a mirror is given by the mirror equation: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] From these two equations, we can calculate the magnification produced by the mirror.
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 
Two capacitors \( C_1 \) and \( C_2 \) are connected in parallel to a battery. Charge-time graph is shown below for the two capacitors. The energy stored with them are \( U_1 \) and \( U_2 \), respectively. Which of the given statements is true? 
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Choke coil is simply a coil having a large inductance but a small resistance. Choke coils are used with fluorescent mercury-tube fittings. If household electric power is directly connected to a mercury tube, the tube will be damaged.
Reason (R): By using the choke coil, the voltage across the tube is reduced by a factor \( \frac{R}{\sqrt{R^2 + \omega^2 L^2}} \), where \( \omega \) is the frequency of the supply across resistor \( R \) and inductor \( L \). If the choke coil were not used, the voltage across the resistor would be the same as the applied voltage.
In light of the above statements, choose the most appropriate answer from the options given below:
