Solution: The standard reduction potentials (SRP) provide insight into the tendency of each ion to undergo reduction:
Understanding Standard Reduction Potential: The higher the value of the standard reduction potential, the greater the tendency to gain electrons (undergo reduction). Hence, ions with higher reduction potentials act as better oxidizing agents.
Comparative Analysis: From the given data: BrO4− has the highest Eo value (1.74 V). IO4− follows with 1.65 V. ClO4− has the lowest at 1.19 V. Thus, the correct order of oxidizing power based on SRP is:
\(\text{BrO}_4^- > \text{IO}_4^- > \text{ClO}_4^-\).
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: