Question:
Oxidation numbers of oxygen in H_2O_2 and H_2O:
Oxidation numbers of oxygen in H_2O_2 and H_2O:
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In H\(_2\)O\(_2\), oxygen has an oxidation number of –1, and in H\(_2\)O, oxygen has an oxidation number of –2.
Updated On: Jan 5, 2026
- –1 and –2
- –2 and –1
- –2 and –2
- 0 and –2
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the oxidation state of oxygen in H\(_2\)O\(_2\).
In hydrogen peroxide (H\(_2\)O\(_2\)), oxygen has an oxidation number of –1, because the total oxidation state of hydrogen is +2 and the molecule is neutral.
Step 2: Understanding the oxidation state of oxygen in H\(_2\)O.
In water (H\(_2\)O), oxygen has an oxidation number of –2, as the total oxidation state of hydrogen is +2 and the molecule is neutral.
Step 3: Conclusion.
Thus, the oxidation numbers of oxygen in H\(_2\)O\(_2\) and H\(_2\)O are –1 and –2, respectively, which corresponds to option (A).
In hydrogen peroxide (H\(_2\)O\(_2\)), oxygen has an oxidation number of –1, because the total oxidation state of hydrogen is +2 and the molecule is neutral.
Step 2: Understanding the oxidation state of oxygen in H\(_2\)O.
In water (H\(_2\)O), oxygen has an oxidation number of –2, as the total oxidation state of hydrogen is +2 and the molecule is neutral.
Step 3: Conclusion.
Thus, the oxidation numbers of oxygen in H\(_2\)O\(_2\) and H\(_2\)O are –1 and –2, respectively, which corresponds to option (A).
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