Question:

An object of mass 1000 g experiences a time-dependent force $ \vec{F} = (2t \hat{i} + 3t^2 \hat{j}) \, \text{N} $. The power generated by the force at time $ t $ is:

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To find the power generated by a force, calculate the dot product of the force and velocity vectors. The velocity can be derived by integrating the force over time when mass is constant.
Updated On: Apr 24, 2025
  • \( (2t^2 + 3t^3) \, \text{W} \)
  • \( (2t^2 + 18t^3) \, \text{W} \)
  • \( (3t^3 + 5t^5) \, \text{W} \)
  • \( (2t^3 + 3t^5) \, \text{W} \)
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The Correct Option is A

Solution and Explanation

We are given:

  • Mass \( m = 1000\, \text{g} = 1\, \text{kg} \)
  • Force \( \vec{F} = (2t \hat{i} + 3t^2 \hat{j}) \)

Step 1: Use Newton’s Second Law to find acceleration:
\[ \vec{a} = \frac{\vec{F}}{m} = 2t \hat{i} + 3t^2 \hat{j} \] 
Step 2: Integrate to find velocity:
\[ \vec{v} = \int \vec{a} \, dt = \int (2t \hat{i} + 3t^2 \hat{j}) \, dt = t^2 \hat{i} + t^3 \hat{j} \] 
Step 3: Power is given by dot product \( \vec{F} \cdot \vec{v} \):
\[ P = (2t \hat{i} + 3t^2 \hat{j}) \cdot (t^2 \hat{i} + t^3 \hat{j}) = 2t^3 + 3t^5 \] \[ \Rightarrow P = 2t^3 + 3t^5 \, \text{W} \]

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